django中使用json做级联选择
使用JSON代替XML做为数据传输是个不错的选择，下面我们看看django中如何使用json。首先下载json-py的类库，http://blog.ntsky.com/wp-content/uploads/json-py-3_4.zip
我们使用关联select作为例子:
<select name="city_id" id="city_id" onChange="getFacilityOptions(this.value)"> {% if city_list %} {% for city in city_list %} <option value="{{city.id}}">{{city.name}}</option> {% endfor %} {% endif %} </select> <select name="facility_id" id="facility_id" style="display:none"> </select>
我们选择city时候关联出facility，这里使用jquery的ajax函数
function getFacilityOptions(city_id){ $.ajax({ type: "GET", url: "/raw/facility_list/"+city_id+"/", dataType: "json", success: function(json){ // 显示设施 $("#facility_id").show(); var facilitySelect = document.getElementById("facility_id"); // 清空 for ( var i=facilitySelect.options.length-1; i>-1; i– ){ facilitySelect = null; } // 创建select选项 for(i=0;i<json.length;i++){ facilitySelect.options = new Option(); facilitySelect.options.text = json.label; facilitySelect.options.value = json.text; } } }) }
通过ajax发送请求得到json数据，然后解析json数据输出select的option
# 城市设施列表 def facility_list(request,city_id): li = [] city = get_object_or_404(City, pk=city_id) facility_list = CityFacility.objects.filter(city=city) for object in facility_list: d = {} d['label'] = object.facility.name d['text'] = object.facility.id li.append(d) return HttpResponse(json.write(li))
这里定义了list,里面包含了一组Dictionary
这样级联选择就OK了。选择city发送ajax请求django，django返回json数据，javascript解析json数据得到facility的select选择。
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