junJZ_2008 发表于 2013-1-23 02:26:33

5、GET与POST方式发送请求参数——ajax基础笔记

GET与POST方式发送请求参数

getAndPostExample.html清单:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN""http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><title>Sending Request Data Using GET and POST</title><script type="text/javascript">var xmlHttp;function createXMLHttpRequest() {    if (window.ActiveXObject) {      xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");    }   else if (window.XMLHttpRequest) {      xmlHttp = new XMLHttpRequest();    }}//拼接查询参数字符串function createQueryString() {    var firstName = document.getElementById("firstName").value;    var middleName = document.getElementById("middleName").value;    var birthday = document.getElementById("birthday").value;    //参数与参数之间用&分隔    var queryString = "firstName=" + firstName + "&middleName=" + middleName      + "&birthday=" + birthday;      return queryString;}//GET方式发送异步请求function doRequestUsingGET() {    createXMLHttpRequest();    //请求一个Servlet    var queryString = "GetAndPostExample?";    //以防读取缓存页面,所以每次发送时多带一个时间参数    queryString = queryString + createQueryString()         + "&timeStamp=" + new Date().getTime();    xmlHttp.onreadystatechange = handleStateChange;    xmlHttp.open("GET", queryString, true);    xmlHttp.send(null);}//POST方式发送请求function doRequestUsingPOST() {    createXMLHttpRequest();    //以防读取缓存页面,所以每次发送时多带一个时间参数    var url = "GetAndPostExample?timeStamp=" + new Date().getTime();    var queryString = createQueryString();      xmlHttp.open("POST", url, true);    xmlHttp.onreadystatechange = handleStateChange;    //POST方式时还要设置以下HTTP头信息    xmlHttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");    //POST方式时参数用send方法发送出去    xmlHttp.send(queryString);}//回调用方法function handleStateChange() {    //状态为4时表示请求已完成    if(xmlHttp.readyState == 4) {      //表示请求的资源存在      if(xmlHttp.status == 200) {            parseResults();      }    }}//处理服务器返回结果function parseResults() {    var responseDiv = document.getElementById("serverResponse");    //如果以前查询过,则清除以前结果    if(responseDiv.hasChildNodes()) {      responseDiv.removeChild(responseDiv.childNodes);    }      var responseText = document.createTextNode(xmlHttp.responseText);    responseDiv.appendChild(responseText);}</script></head><body><h1>Enter your first name, middle name, and birthday:</h1>    <table>    <tbody>      <tr>            <td>First name:</td>            <td><input type="text" id="firstName"/>      </tr>      <tr>            <td>Middle name:</td>            <td><input type="text" id="middleName"/>      </tr>      <tr>            <td>Birthday:</td>            <td><input type="text" id="birthday"/>      </tr>    </tbody>    </table>    <form action="#">    <input type="button" value="Send parameters using GET" />            <br/><br/>    <input type="button" value="Send parameters using POST" />      </form><br/><h2>Server Response:</h2><!-- 存放结果区 --><div id="serverResponse"></div></body></html> GetAndPostExample.java清单:
package ajaxbook.chap3;import java.io.*;import java.net.*;import javax.servlet.*;import javax.servlet.http.*;public class GetAndPostExample extends HttpServlet {      protected void processRequest(HttpServletRequest request,             HttpServletResponse response, String method)    throws ServletException, IOException {                //设置响应头类型text/xml      response.setContentType("text/xml");                //获取用户输入参数   String firstName = request.getParameter("firstName");      String middleName = request.getParameter("middleName");      String birthday = request.getParameter("birthday");                //创建返回文本      String responseText = "Hello " + firstName + " " + middleName                + ". Your birthday is " + birthday + "."                + " ";                //向浏览器写回响应信息      PrintWriter out = response.getWriter();      out.println(responseText);      //关闭流      out.close();    }      protected void doGet(HttpServletRequest request, HttpServletResponse response)    throws ServletException, IOException {      //处理GET请求      processRequest(request, response, "GET");    }      protected void doPost(HttpServletRequest request, HttpServletResponse response)    throws ServletException, IOException {      //处理POST请求      processRequest(request, response, "POST");    }} 运行结果:
 
http://dl.iteye.com/upload/attachment/157624/8b49473b-3065-3e6b-ad3f-7801b7385e87.gif
 
 
页: [1]
查看完整版本: 5、GET与POST方式发送请求参数——ajax基础笔记