PL/SQLcookbook 第一章
一、返回记录1） 返回所有行和列
1 select *2 from emp使用*效率不高,应该把所有列列出来:
select empno,ename,job,sal,mgr,hiredate,comm,deptno from emp
2） 从table返回行
在where子句中使用=, <, >, <=, >=, !,<>约束返回行，当有多个约束条件，可以使用and, or
1 select *2 from emp3 where deptno = 10
select * from emp where ( deptno = 10 or comm is not null or sal <= 2000 ) and deptno=20 EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO ----- ------ ----- ----- ----------- ----- ---------- ------ 7369 SMITH CLERK 7902 17-DEC-1980 800 20 7876 ADAMS CLERK 7788 12-JAN-1983 1100 20
3）
4）指定返回列，把所需列放入select子句：
1 select ename,deptno,sal2 from emp
5）别名：当你需要返回的列名更易读和理解时使用别名，其中as可以省略
1 select sal,comm2 from emp1 select sal as salary, comm as commission2 from emp SALARY COMMISSION ------- ---------- 800 1600 300 1250 500 2975 1250 1300 2850 2450 3000 5000 1500 0 1100 950 3000 13006）别名可以在其它子句中被使用：
1 select * 2 from ( 3 select sal as salary, comm as commission 4 from emp 5 ) x 6 where salary < 50007）连接多列：
DB2, Oracle, PostgreSQL
1 selectename||' WORKS AS A '||job as msg
2 from emp
3 where deptno=10
MySQL
1 selectconcat(ename, ' WORKS AS A ',job) as msg
2 from
3 where deptno=10
SQL Server
1 selectename + ' WORKS AS A ' + job as msg
2 from emp
3 where deptno=10
8）使用逻辑运算处理返回：
1 select ename,sal, 2 case when sal <= 2000 then 'UNDERPAID' 3 when sal >= 4000 then 'OVERPAID' 4 else 'OK' 5 end as status 6 from emp译者注：when 后面的条件子句和where是一样的，可以使用and,或者or，在mySql和oracle中测试：
在Oracle/PL/SQL手册中：
Compound IF Statements
--复合if条件语句
If the last name is Vargas and the salaryis more than 6500:
-- last name 等于Vargas，并且the salary大于6500
Set department number to 60
. . .
IF v_ename = ’Vargas’ AND salary > 6500THEN
v_deptno := 60;
END IF;
. . .
9）限制返回行数：
DB2
1 select *
2 from emp fetch first 5 rows only
MySQL and PostgreSQL
1 select *
2 from emp limit 5
Oracle
1 select *
2 from emp
3 where rownum <= 5
SQL Server
1 select top5 *
2 from emp
Many vendors provide clauses such as FETCHFIRST and LIMIT that let you specify the number of rows to be returned from aquery. Oracle is different, in that you must make use of a function calledROWNUM that returns a number for each row returned (an increasing valuestarting from 1).
Here is what happens when you use ROWNUM<= 5 to return the first five rows:
1. Oracle executes your query.
2. Oracle fetches the first rowand calls it row number 1.
3. Have we gotten past row number5 yet? If no, then Oracle returns the row, because it meets the criteria ofbeing numbered less than or equal to 5. If yes, then Oracle does not return therow.
4. Oracle fetches the next row andadvances the row number (to 2, and then to 3, and then to 4, and so forth).
5. Go to step 3.
Using an equality condition in conjunctionwith ROWNUM is a bad idea. Here is what happens when you try to return, say,the fifth row using ROWNUM = 5:
1. Oracle executes your query.
2. Oracle fetches the first rowand calls it row number 1.
3. Have we gotten to row number 5yet? If no, then Oracle discards the row, because it doesn't meet the criteria.If yes, then Oracle returns the row. But the answer will never be yes!
4. Oracle fetches the next row andcalls it row number 1. This is because the first row to be returned from thequery must be numbered as 1.
5. Go to step 3.
Study this process closely, and you can seewhy the use of ROWNUM = 5 to return the fifth row fails. You can't have a fifthrow if you don't first return rows one through four!
10）返回任取的n条:
DB2
1 selectename,job
2 from emp
3 order by rand() fetch first 5 rows only
MySQL
1 selectename,job
2 from emp
3 order by rand() limit 5
PostgreSQL
Use the built-in RANDOM function in conjunctionwith LIMIT and ORDER BY:
1 selectename,job
2 from emp
3 order by random()limit 5
Oracle
1 select *
2 from (
3 select ename, job
4 from emp
6 order by dbms_random.value()
7 )
8 where rownum <= 5
SQL Server
1 select top5 ename,job
2 from emp
3 order by newid()
上面都是基于排序的，下面oracle例子:
select *
from (
select dbms_random.value() num
from emp
)
where rownum <= (5+ num) and rownum >=num
11) null：1 select * 2 from emp 3 where comm is null12)null转化：
select case when comm is null then 0 else comm end from emporacle中： 1 select nvl(comm,0) 2 from emp12)字段字符匹配,like： 1 select ename, job 2 from emp 3 where deptno in (10,20) 4 and (ename like '%I%' or job like '%ER')
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