liferay 权限策略
先上一张大家都很熟悉的图http://dl.iteye.com/upload/attachment/432432/5095700f-ae44-3f42-b634-47220fce6376.png
这张图可以说是整个liferay的核心，他和权限密不可分，在权限体系里，每一个箭头和UI设置和API一一对应，今天讲权限，不讲代码只讲理论。liferay的权限策略分为五种，默认是采用第五种，因为第五种性能最好，如果要修改则在portal-ext.properies加上permissions.user.check.algorithm=3
讲策略之前我们先讲一下，liferay权限分为几种
A:Group Role Permission: 用户加入的Group(Community/Organization)所拥有的角色的权限
Is the user connected to one of the permissions via group or organization roles?
<sql id="com.liferay.portal.service.persistence.PermissionFinder.countByGroupsRoles"><!) AND([$GROUP_IDS$])]]></sql>
B:Group Permission: 分配给Group(包括Community/Organization/User Group三类Group)的权限
Is the user associated with groups or organizations that are directly connected to one of the permissions?
<sql id="com.liferay.portal.service.persistence.PermissionFinder.countByGroupsPermissions"><!) AND([$GROUP_IDS$])]]></sql>
C:User Role Permission: 分配给用户Regular类型角色的权限
Is the user connected to one of the permissions via user roles?
<sql id="com.liferay.portal.service.persistence.PermissionFinder.countByUsersRoles"><!) AND(Users_Roles.userId = ?)]]></sql>
D:User Group Role Permission: 用户加Group(Community/Organization)所拥有该社区角色的权限
Is the user connected to one of the permissions via user group roles?
<sql id="com.liferay.portal.service.persistence.PermissionFinder.countByUserGroupRole"><!) AND(UserGroupRole.userId = ?)]]></sql>
E:User Permission: 直接分配给user的权限
Is the user directly connected to one of the permissions?
<sql id="com.liferay.portal.service.persistence.PermissionFinder.countByUsersPermissions"><!) AND(Users_Permissions.userId = ?)]]></sql>
F:Role Permission: 分配给角色(包括Regular/Community/Organization三种类型角色)的权限
Is the user associated with a role that is directly connected to one of the permissions?
<sql id="com.liferay.portal.service.persistence.PermissionFinder.countByUsersPermissions"><!) AND(Users_Permissions.userId = ?)]]></sql>
讲完了这check权限的分类，我们现在开始讲liferay的权限策略
Algorithm 1. A or B or C or D or E
Algorithm 2. A and B and C and D and E
Algorithm 3. B or E or F
Algorithm 4. B and E and F
Algorithm 5. F
注意：liferay推荐使用第五种是因为他效率最高，第一、二种是不可能会用到的，因为那是早期版本的设计，有些表例如：Groups_Roles都已经放弃了。如果不是必须不要去修改策略。
现在说说他的缺点：用过权限开发的人都会发现，他的权限粒度很高，这样带来了一个问题就是效率会变低（虽然他用了大量的cache），最讨厌的是liferay权限体系总是，先把数据全搜索出来，当你要进行操作（VIEW）时，他才会跳出个红框框告诉你，你没有权限，这样很不友好。最典型的是list分页，点其中一条才会告诉你没权限，客户居然投诉：说我们有诱导之嫌。liferay现有的api是肯定做不到直接搜索出合法数据，虽然liferay在有的元素的service层，先把数据全取出来然后再一个一个的过滤来达到这样的效果，这样我觉得实在无法容忍，为了一页20条的数据，你居然要搜索出所有数据。为此我在项目中专门写了一个类，把一些共用的权限sql写了出来
public static String getPrimkeyByRolePermission(long companyId, String name, int scope, String actionId, String roleIds){StringBuffer sql = new StringBuffer();sql.append("SELECT DISTINCT RESOURCE_.PRIMKEY FROM RESOURCE_ "+"LEFT JOIN RESOURCECODE ON (RESOURCE_.CODEID = RESOURCECODE.CODEID) "+"LEFT JOIN PERMISSION_ ON (PERMISSION_.RESOURCEID = RESOURCE_.RESOURCEID) "+"LEFT JOIN ROLES_PERMISSIONS ON (PERMISSION_.PERMISSIONID = ROLES_PERMISSIONS.PERMISSIONID) ");sql.append("WHERE RESOURCECODE.COMPANYID = "+ companyId +" " +"AND RESOURCECODE.NAME = '"+ name +"' AND RESOURCECODE.SCOPE = "+ scope +" ");sql.append("ANDPERMISSION_.COMPANYID = "+ companyId +" AND PERMISSION_.ACTIONID = '"+ actionId +"' AND " +"ROLES_PERMISSIONS.ROLEID IN ("+ roleIds +")");return sql.toString();}public static String getPrimkeyByRolePermission(long companyId,String name, int scope, String actionId, long userId){StringBuffer sql = new StringBuffer();sql.append("SELECT DISTINCT RESOURCE_.PRIMKEY FROM RESOURCE_ "+"LEFT JOIN RESOURCECODE ON (RESOURCE_.CODEID = RESOURCECODE.CODEID) "+"LEFT JOIN PERMISSION_ ON (PERMISSION_.RESOURCEID = RESOURCE_.RESOURCEID) "+"LEFT JOIN USERS_PERMISSIONS ON (PERMISSION_.PERMISSIONID = USERS_PERMISSIONS.PERMISSIONID) ");sql.append("WHERE RESOURCECODE.COMPANYID = "+ companyId +" " +"AND RESOURCECODE.NAME = '"+ name +"' AND RESOURCECODE.SCOPE = "+ scope +" ");sql.append("ANDPERMISSION_.COMPANYID = "+ companyId +" AND PERMISSION_.ACTIONID = '"+ actionId +"' AND " +"USERS_PERMISSIONS.USERID = " + userId) ;return sql.toString();}public static String getPrimkeyByGroupPermission(long companyId,String name, int scope, String actionId, long userId, long groupId){StringBuffer sql = new StringBuffer();sql.append("SELECT DISTINCT RESOURCE_.PRIMKEY FROM RESOURCE_ "+"LEFT JOIN RESOURCECODE ON (RESOURCE_.CODEID = RESOURCECODE.CODEID) "+"LEFT JOIN PERMISSION_ ON (PERMISSION_.RESOURCEID = RESOURCE_.RESOURCEID) "+"LEFT JOIN GROUPS_PERMISSIONS ON (PERMISSION_.PERMISSIONID = GROUPS_PERMISSIONS.PERMISSIONID) +" +"LEFT JOIN USERS_GROUPS ON (GROUPS_PERMISSIONS.GROUPID = USERS_GROUPS.GROUPID) ");sql.append("WHERE RESOURCECODE.COMPANYID = "+ companyId +" " +"AND RESOURCECODE.NAME = '"+ name +"' AND RESOURCECODE.SCOPE = "+ scope +" ");sql.append("ANDPERMISSION_.COMPANYID = "+ companyId +" AND PERMISSION_.ACTIONID = '"+ actionId +"' AND " +"GROUPS_PERMISSIONS.GROUPID = " + groupId +" AND " +"USERS_GROUPS.USERID = " + userId) ;return sql.toString();}public static String getPrimkeyByPermissionAlgorithm3(long companyId,String name, int scope, String actionId, long userId, long groupId){StringBuffer sql = new StringBuffer();sql.append("SELECT DISTINCT RESOURCE_.PRIMKEY ID FROM RESOURCE_, RESOURCECODE, PERMISSION_, ");sql.append("(");sql.append("SELECT ROLES_PERMISSIONS.PERMISSIONID FROM ROLES_PERMISSIONS " +"JOIN USERS_ROLES ON (ROLES_PERMISSIONS.ROLEID = USERS_ROLES.USERID) " +"WHERE USERS_ROLES.USERID = " + userId);sql.append(") AS R, ");sql.append("(");sql.append("SELECT USERS_PERMISSIONS.PERMISSIONID FROM USERS_PERMISSIONS " +"WHERE USERS_PERMISSIONS.USERID = " + userId);sql.append(") AS U, ");sql.append("(");sql.append("SELECT GROUPS_PERMISSIONS.PERMISSIONID FROM GROUPS_PERMISSIONS " +"JOIN USERS_GROUPS ON (GROUPS_PERMISSIONS.GROUPID = USERS_GROUPS.GROUPID) " +"WHERE USERS_GROUPS.GROUPID = " + groupId);sql.append(") AS G ");sql.append("WHERE RESOURCECODE.COMPANYID = "+ companyId +" " +"AND RESOURCECODE.NAME = '"+ name +"' AND RESOURCECODE.SCOPE = "+ scope +" ");sql.append("ANDPERMISSION_.COMPANYID = "+ companyId +" AND PERMISSION_.ACTIONID = '"+ actionId + "' ") ;sql.append("AND RESOURCE_.CODEID = RESOURCECODE.CODEID "+"AND PERMISSION_.RESOURCEID = RESOURCE_.RESOURCEID ");sql.append("AND (PERMISSION_.PERMISSIONID = R.PERMISSIONID OR " +"PERMISSION_.PERMISSIONID = U.PERMISSIONID OR " +"PERMISSION_.PERMISSIONID = G.PERMISSIONID)" );return sql.toString();}
注意：我们到的是策略3,所以我分别写了B,E,F权限SQL,及一个总的Algorithm3SQL,这些SQL返回的都是你要搜索元素的key，这些SQL在liferay中是通用的，只要你是用的liferay的权限他都是合适的，你要把他放在你sql合适的位置，注意最好不要使用in，这样效率是比较低的。
页:
[1]