prototype ajax传递参数乱码解决方法
1.JSP文件function ajaxReq(){
var url = "ChatRoomServlet";
var param = "fname=${param.fname}&tname=${param.tname}";
new Ajax.Request(url,{
method:"get",
parameters:encodeURI(param),
requestHeaders:['Cache-Control','no-cache','If-Modified-Since','0'],
onSuccess:function(httpObj){
$("chatarea").value = httpObj.responseText;
},
onFailure:function(httpObj){
}
});
2.servlet的doGet方法：
String fname = request.getParameter("fname");
fname = new String(fname.getBytes("ISO-8859-1"),"UTF-8");
页:
[1]