parsexml.html

xiejiaohui · 发表于 2013-2-7 20:02:15

例子来源：《Ajax 基础教程》金灵等译这本书非常不错

parsexml.html

<html><head><title>Parsing XML Responses with the W3C DOm</title><script>var xmlHttp;var requestType = "";function createXMLHttpRequest() {if (window.ActiveXObject) {xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");}else if (window.XMLHttpRequest) {xmlHttp = new XMLHttpRequest();}}function startRequest(requestedList) {requestType = requestedList;createXMLHttpRequest();xmlHttp.onreadystatechange = handleStateChange;xmlHttp.open("GET", "parseXML.xml", true);xmlHttp.send(null);}function handleStateChange() {if(xmlHttp.readyState == 4) {if(xmlHttp.status == 200) {if(requestType == "north") {listNorthStates();}else if(requestType == "all") {listAllStates();}}}}function listNorthStates() {var xmlDoc = xmlHttp.responseXML;var northNode = xmlDoc.getElementsByTagName("north")[0];var northStates = northNode.getElementsByTagName("state");outputList("Northern states", northStates);}function listAllStates() {var xmlDoc = xmlHttp.responseXML;var allStates = xmlDoc.getElementsByTagName("state");outputList("All States in Document", allStates);}function outputList(title, states) {var out = title;var currentState = null;for(var i = 0; i < states.length; i++) {currentState = states[i];out = out + "\n- " + currentState.childNodes[0].nodeValue;}alert(out);}</script></head><body><h1>Process XML Document of U.S.States</h1><br /><br /><form action="#"><input type="button" value="View All Listed States" /><input type="button" value="View All Listed Northern States" /></form></body></html>

parseXML.xml

<?xml version="1.0" encoding="UTF-8"?><states><north><state>Minnesota_1</state><state>Iowa_1</state><state>North Dakota_1</state></north><south><state>Texas</state><state>Oklahoma</state><state>Louisiana</state></south><east><state>New York</state><state>North Carolina</state><state>Massachusetts</state></east><west><state>California</state><state>Oregon</state><state>Nevada</state></west></states>

		自动登录	找回密码
密码			立即注册

parsexml.html

浏览过的版块