第九题

linuke

public class Task_9 {/** * 已知现在有唯一的自然数三元组(a,b,c)满足： a≤b≤c 且 a2+b2=c2 且 a+b+c = 1000 求a×b×c的值。 *  * @param args */public static void main(String[] args) {for (int a = 1; a < 500; a++) {for (int b = 1; b < 500; b++) {if ((a * a + b * b) == (1000 - a - b) * (1000 - a - b)&& (a < b) && (b < (1000 - a - b))) {System.out.println("a = " + a);System.out.println("b = " + b);System.out.println(a * b * (1000 - a - b));}}}for (int i = 1; i < 1000; i++)for (int k = 1; k < 1000; k++) {if (Math.sqrt(Math.pow(i, 2) + Math.pow(k, 2)) + k + i == 1000&& (i < k) && (i < (1000 - i - k))) {System.out.println("i = " + i);System.out.println("k = " + k);System.out.println(i * k * (1000 - i - k));}}}}